標題:
maths問題!!! Form 1 程度 !!!
發問:
麻煩有識之士解答一下下面的問題,thz!!! In Beijing Olympics 2008,the number of gold medals won by China is 30 more than the number of silver medals, and the ratio of the number of silver medals and bronze medals is 3:4. if China won 100 medals in total, find the no. of gold medals obtained!!
最佳解答:
Let x be the number of silver x+30+x+4x/3=100 10x/3=70 x=21 since the number of gold is 30 more than the number of silver x+30 =21+30 =51 thus there were 51 of gold medals obtained by China in Beijing Olympics 2008. Maths check Gold meals + silver meals +bronze meals=100 51+21+4*21/3 =100
Let's A = nos of gold medal; B = nos of silver medal; C = nos of bronze medal we know : (1) B = A - 30 (2) C = 4/3 B (3) A + B + C = 100 Therefore (3) :- A + (A - 30) + 4/3 (A-30) = 100 10/3 A - 30 - 40 = 100 10/3 A = 170 A = 51
maths問題!!! Form 1 程度 !!!
發問:
麻煩有識之士解答一下下面的問題,thz!!! In Beijing Olympics 2008,the number of gold medals won by China is 30 more than the number of silver medals, and the ratio of the number of silver medals and bronze medals is 3:4. if China won 100 medals in total, find the no. of gold medals obtained!!
最佳解答:
Let x be the number of silver x+30+x+4x/3=100 10x/3=70 x=21 since the number of gold is 30 more than the number of silver x+30 =21+30 =51 thus there were 51 of gold medals obtained by China in Beijing Olympics 2008. Maths check Gold meals + silver meals +bronze meals=100 51+21+4*21/3 =100
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其他解答:Let's A = nos of gold medal; B = nos of silver medal; C = nos of bronze medal we know : (1) B = A - 30 (2) C = 4/3 B (3) A + B + C = 100 Therefore (3) :- A + (A - 30) + 4/3 (A-30) = 100 10/3 A - 30 - 40 = 100 10/3 A = 170 A = 51
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