標題:
中二數學問題(最快者有20分)
發問:
因式分解下列各式。1)p(xy-xz)+q(y-z)2)(x-1)y+1-x3)x(y-z)-y+z4)(x-y)2次方+z(y-x)5)x(ab-ac)+y(ac-ab)6)(a+b)2次方-ax-bx7)(x-y)2次方+2x+2y8)x 2次方-19)64-49x 2次方10)(2-x)2次方-25x 2次方11)x 2次方+6x+912)x 2次方+4xy+4y 2次方13)4(x-y)2次方+4a(x-y)+a 2次方14)x 2次方-3x+215)x 2次方-5x+616)x 2次方+2x-3517)x 2次方-6x-2718)x 2次方-5xy+6y... 顯示更多 因式分解下列各式。 1)p(xy-xz)+q(y-z) 2)(x-1)y+1-x 3)x(y-z)-y+z 4)(x-y)2次方+z(y-x) 5)x(ab-ac)+y(ac-ab) 6)(a+b)2次方-ax-bx 7)(x-y)2次方+2x+2y 8)x 2次方-1 9)64-49x 2次方 10)(2-x)2次方-25x 2次方 11)x 2次方+6x+9 12)x 2次方+4xy+4y 2次方 13)4(x-y)2次方+4a(x-y)+a 2次方 14)x 2次方-3x+2 15)x 2次方-5x+6 16)x 2次方+2x-35 17)x 2次方-6x-27 18)x 2次方-5xy+6y 2次方 19) (a)因式分解 x 2次方-10x+25。 (b)利用(a)部結果,或其他方法,因式分解(x+1)2次方-10(x+1)+25。 20) (a)因式分解 x 2次方-4x+3。 (b)利用(a)部結果,或其他方法,因式分解(2x-3)2次方-4(2x-3)+3
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最佳解答:
(1) p(xy-xz)+q(y-z) =px(y-z)+q(y-z) =(px+q)(y-z) (2) (x-1)y+1-x =(x-1)y-(x-1) =(x-1)(y-1) (3) x(y-z)-y+z =x(y-z)-(y-z) =(x-1)(y-z) (4) (x-y)2+z(y-x) =(x-y)2-z(x-y) =(x-y)[(x-y)-z] =(x-y)(x-y-z) (5) x(ab-ac)+y(ac-ab) =x(ab-ac)-y(ab-ac) =(x-y)(ab-ac) =a(x-y)(b-c) (6) (a+b)2-ax-bx =(a+b)2-(a+b)x =(a+b)(a+b-x) (7) 無法分解 (8) x2-1 =x2-12 =(x+1)(x-1) (9) 64-49x2 =82-(7x)2 =(8+7x)(8-7x) (10) (2-x)2-25x2 =(2-x)2-(5x)2 =(2-x+5x)(2-x-5x) =(2+4x)(2-6x) (11) x2+6x+9 =(x+3)2 (12) x2+4xy+4y2 =(x+2y)2 (13) 4(x-y)2+4a(x-y)+a2 =[2(x-y)+a]2 =(2x-2y+a)2 (14) x2-3x+2 =(x-1)(x-2) (15) x2-5x+6 =(x-2)(x-3) (16) x2-2x+35 =(x+5)(x-7) (17) x2-6x-27 =(x+3)(x-9) (18) x2-5xy+6y2 =(x-2y)(x-3y) (19) (a) x2-10x+25 =(x-5)2 (b) (x+1)2-10(x+1)+25 =(x+1-5)2 =(x-4)2 (20) (a) x2-4x+3 =(x-1)(x-3) (b) (2x-3)2-4(2x-3)+3 =(2x-3-1)(2x-3-3) =(2x-4)(2x-6) =4(x-2)(x-3)
其他解答:
(1) p(xy-xz)+q(y-z) =px(y-z)+q(y-z) =(px+q)(y-z) (2) (x-1)y+1-x =(x-1)y-(x-1) =(x-1)(y-1) (3) x(y-z)-y+z =x(y-z)-(y-z) =(x-1)(y-z) (4) (x-y)2+z(y-x) =(x-y)2-z(x-y) =(x-y)[(x-y)-z] =(x-y)(x-y-z) (5) x(ab-ac)+y(ac-ab) =x(ab-ac)-y(ab-ac) =(x-y)(ab-ac) =a(x-y)(b-c) (6) (a+b)2-ax-bx =(a+b)2-(a+b)x =(a+b)(a+b-x) (7) 無法分解 (8) x2-1 =x2-12 =(x+1)(x-1) (9) 64-49x2 =82-(7x)2 =(8+7x)(8-7x) (10) (2-x)2-25x2 =(2-x)2-(5x)2 =(2-x+5x)(2-x-5x) =(2+4x)(2-6x) (11) x2+6x+9 =(x+3)2 (12) x2+4xy+4y2 =(x+2y)2 (13) 4(x-y)2+4a(x-y)+a2 =[2(x-y)+a]2 =(2x-2y+a)2 (14) x2-3x+2 =(x-1)(x-2) (15) x2-5x+6 =(x-2)(x-3) (16) x2-2x+35 =(x+5)(x-7) (17) x2-6x-27 =(x+3)(x-9) (18) x2-5xy+6y2 =(x-2y)(x-3y) (19) (a) x2-10x+25 =(x-5)2 (b) (x+1)2-10(x+1)+25 =(x+1-5)2 =(x-4)2 (20) (a) x2-4x+3 =(x-1)(x-3) (b) (2x-3)2-4(2x-3)+3 =(2x-3-1)(2x-3-3) =(2x-4)(2x-6) =4(x-2)(x-3)