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標題:
PHYSICS UNIVERSITY( ROTATION
發問:
A turntable rotates with a constant angular acceleration 2.50rad/s 2 rad/s^2 . After a time interval 3.75s s the wheel has rotated through an angle of 57.0rad What was the angular velocity of the wheel at the beginning of the time interval 3.75s s ?
最佳解答:
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Use equation: s = ut + (1/2)at^2 with s = 57 rad, t = 3.75 s, a = 2.5 rad/s^2, u = ? hence, 57 = (3.75)u + (1/2).(2.5).(3.75)^2 u = 10.5 rad/s
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