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標題:

F.2 math!!!! Quick!!

發問:

1) 81x^2+40x+5 2) factorize -288p^2+18r^2+48pq-2q^2 3) 49a^2-64 4) -p^2q^2+r^4 5) a^2-b^2+bc-ac 6) 4c^2-2c-9d^2-3d

最佳解答:

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1) 81x^2+40x+5,it cannot be factorize Or 80x^2+40x+5 =5(4x+1)^2 2) -288p^2+18r^2+48pq-2q^2 =2(-144p^2+9r^2+24pq-q^2) =2(-(12p-q)^2+9r^2) =2(3r+12p-q)(3r-12p+q) 3) 49a^2-64 =(7a-8)(7a+8) 4) -p^2q^2+r^4 =r^4-(pq)^2 =(r^2+pq)(r^2-pq) 5) a^2-b^2+bc-ac =(a+b)(a-b)-c(a-b) =(a+b-c)(a-b) 6) 4c^2-2c-9d^2-3d =(2c+3d)(2c-3d)-(2c+3d) =(2c+3d)(2c-3d-1)

其他解答:

1:F2 5會計到~你可能抄錯 答案係 81x^2+40x+5=[9x+20/9-(√-5)/9)][9x+20/9+(√-5)/9] 2: -288p^2+18r^2+48pq-2q^2 =-2(144p^2-24pq+q^2-9r^2) =-2[(12p-q)^2-(3r)^2] =-2(12p-q-3r)(12p-q+3r)// 3:49a^2-64 =(7a)^2-8^2 =(7a+8)(7a-8)// 4:-p^2q^2+r^4 =-[(pq)^2-(r^2)^2 = -(pq-r^2)(pq+r^2) =(r^2-pq)(r^2+pq)// 5:a^2-b^2+bc-ac =(a+b)(a-b)+c(b-a) =(a+b)(a-b)-c(a-b) =(a+b-c)(a-b)// 6:4c^2-2c-9d^2-3d =4c^2-9d^2-2c-3d =(2c-3d)(2c+3d)-(2c+3d) =(2c-3d-1)(2c+3d)//