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標題:

請解答數學問題

發問:

2X1 + 1X2 = 22 3X1 + 3X2 = 39 求 X1, X2 答案: X1= 9 , X2= 4 2X + Y = 16 4X + 6Y = 48 求 X, Y 答案: X= 4 , Y= 6 我想問計呢兩條數既過程, 點樣求?

最佳解答:

2X1 + 1X2 =22 -------i 3X1 + 3X2 =39 -------ii from i X1 = (22-X2)/2 from ii X1 = (39-3X2)/3 = 13-X2 22-X2)/2 = 13-X2 22-X2 = 26-2X2 X2 = 4 代X2 = 4 入i 2X1 + 4 = 22 X1 = 9 2X+Y = 16 ------i 4X+6Y=48 ------ii from i Y = 16-2X from ii Y = (48-4X)/6 16-2X = (48-4X)/6 96-12X = 48-4X 48 = 8X X = 6 代X = 6入i 12+Y=16 Y=4

其他解答:B5117735D6B60D95