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標題:
(-7+10i)+(9+6i)除(3i)=.....
發問:
最佳解答:
究竟係 [ (-7+10i) + (9+6i) ] / 3i 定係 (-7+10i) + [(9+6i)/(3i) ] 2010-10-01 22:32:39 補充: * 假設題目為 (-7+10i) + [ (9+6i) / 3i ] (-7+10i) + [ (9+6i) / 3i ] = ( -7+10i) + (9/3i) + 2 = -7 + 10i + (-3i) +2 = ( -5 + 7i ) 2010-10-02 23:16:34 補充: a/bi = ai / bi^2 = -ai/b
其他解答:
【Complex number solution】 =-7+10i + (0+18)/9 - 27i/9, conjugate conjugate = -7 +10i + 2 -3i = -5 +7i 2010-10-01 23:41:47 補充: i, may represent imaginary part|||||(-7+10i)+(9+6i)除(3i) =-7+10i+9+6i除3i =-7+10i+9+2i =-7+9+10i=2i =2+12i5AEEC82B53E1B405
(-7+10i)+(9+6i)除(3i)=.....
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(-7+10i)+(9+6i)除(3i)=咩 請列明步驟 更新: a/bi=-bi?最佳解答:
究竟係 [ (-7+10i) + (9+6i) ] / 3i 定係 (-7+10i) + [(9+6i)/(3i) ] 2010-10-01 22:32:39 補充: * 假設題目為 (-7+10i) + [ (9+6i) / 3i ] (-7+10i) + [ (9+6i) / 3i ] = ( -7+10i) + (9/3i) + 2 = -7 + 10i + (-3i) +2 = ( -5 + 7i ) 2010-10-02 23:16:34 補充: a/bi = ai / bi^2 = -ai/b
其他解答:
【Complex number solution】 =-7+10i + (0+18)/9 - 27i/9, conjugate conjugate = -7 +10i + 2 -3i = -5 +7i 2010-10-01 23:41:47 補充: i, may represent imaginary part|||||(-7+10i)+(9+6i)除(3i) =-7+10i+9+6i除3i =-7+10i+9+2i =-7+9+10i=2i =2+12i5AEEC82B53E1B405
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